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A Graphical Analysis

It is useful in general to have a geometrical picture, called a state space or phase space plot, which shows how the next iterate $x_{n+1}$ depends on the current value $x_n$. This is done as follows. First draw the curve $y=f(x)$ to represent the right hand side of Eq.(3.1) . On the same graph plot the line $y=x$ to represent the iteration process $x_{n+1}=f(x_n)$. Fig(3.1a) illustrates the method for the case $f(x)=x^2$. Starting with any $x_0$, for example $x_0=0.8$, the next value $x_1=f(x_0)$ is obtained by drawing a vertical line from $x_0=0.8$ to the curve $y=x^2$. Since $x_1=f(x_0)$ is now needed as the next input to the iterative map, graphically this is achieved by moving horizontally to the $y=x$ line and then moving vertically to the 'square' curve to give $x_2$. The procedure is repeated to produce a generic 'cobweb' diagram. For this example Fig(3.1a) shows a step-wise approach to the fixed point at the origin.
\epsfbox{f3.1a.eps}



It is easy to see from this diagram that for the example considered, the origin is an attractive (stable) fixed point with a basin of attraction $[0,1)$, while as Fig(3.1b) shows, the point $x^{*}=1$ is an unstable fixed point.
\epsfbox{f3.1b.eps}



Since the fixed points above correspond to a situation where the future values of $x$ at each time step remain the same, they are called period-one fixed points. This terminology is introduced as we will later generalise the concept of fixed points. Since period-one fixed points correspond to solutions of $x_{n+1} = x_n$, graphically these can be found from the intersection of the mapping function $y=f(x)$ with the staright line $y=x$. For the case $f(x)=x^2$, the two intersections are at the origin and at $x=1$ as we already know.
next up previous contents
Next: The Analytical Approach Up: A Simple Example of Previous: An Intuitive Analysis   Contents
Rajesh Parwani 2002-01-03